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5x^2+53x-8=0
a = 5; b = 53; c = -8;
Δ = b2-4ac
Δ = 532-4·5·(-8)
Δ = 2969
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(53)-\sqrt{2969}}{2*5}=\frac{-53-\sqrt{2969}}{10} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(53)+\sqrt{2969}}{2*5}=\frac{-53+\sqrt{2969}}{10} $
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